solve algebraically for all values of x 81^x^3+2x^2=27^5x/3

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1 Answer

A few parantheses may be needed: 81^(x^3+2x^2)=27^(5x/3)?

3^4(x^3+2x^2)=3^3(5x/3)=3^5x

Equating exponents: 4x^3+8x^2=5x; x(4x^2+8x-5)=0

x(2x-1)(2x+5)=0; x=0, 1/2, -5/2.
by Top Rated User (1.2m points)

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