how can we factorise 1) 4x^2+3x-1 and 2) 2x^3-250

How can we factorise the two problems given completely. :)
in Factors of a number by Level 1 User (160 points)

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1 Answer

  1. We need factors of 4 whose difference is 3: 4 and 1 fit. So factorise: (4x-1)(x+1).
  2. Take out the common factor 2: 2(x^3-125), then we can see that x=5 is a zero of the cubic, so (x-5) is a factor and x^3-125 can be divided by x-5 to find the other factor: x^2+5x+25. The solution is

2(x-5)(x^2+5x+25)

by Top Rated User (776k points)

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