Sum of 1/1×2, 1/2×3, 1/3×4,.......1/28×29, 1/29×30
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1 Answer

Each term could be written (n+1)/n where 1≤n≤29, where n is an integer (whole number).

The sum can be expressed as ∑129(n+1)/n=∑129(​1+1/n)=29+∑129​(​1/n).

So we need the sum of the reciprocals of natural numbers up to 29.

This sum is 3.9616538 approx. So the sum is 32.9616538 approx.

by Top Rated User (1.2m points)

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