tan^2 theta/square root 1+tan ^2 theta
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1 Answer

tan2θ/√(1+tan2θ)=

tan2θ/√sec2θ=

tan2θ/secθ=

cosθtan2θ=

cosθ(sin2θ/cos2θ)=

sinθ.sinθ/cosθ=sinθtanθ.

by Top Rated User (1.2m points)

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