x^2+4px+4p^2=0 find the range of p

frown i tried everything i know still can't please help

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1 Answer

x²+4px+4p²=0, (x+2p)²=0, x+2p=0, p=-½x.

The range of p is the same as the domain (x), that is, unbounded (-∞,∞).

There is a linear relationship between p and x—they lie on a straight line.

by Top Rated User (1.2m points)

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