(10 cos squair)10pi t=[10/2(cos20 pi/t+1)]

To prove that. (10 cos squire )10 pi,t =10/2 (cos 20pi/t+1) Solve the eqation
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cos(2x)=2cos2(x)-1, cos2(x)=½(cos(2x)+1) (trig identity), multiply through by 10:

10cos2(x)=(10/2)(cos(2x)+1).

Let x=10π/t:

10cos2(10π/t)=(10/2)(cos(20π/t)+1). QED

ago by Top Rated User (1.2m points)

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