Question

the ratio of two integers is 7:12. their sum is 76. find the two integers

Answer 1

1) 7x = 12y

2) x + y = 76  or x = 76 - y

substitute eq(2) into eq(1):

7(76 - y) = 12y

532 - 7y = 12y

532 = 19y

y = 532/19 = 28

using eq(2):

x = 76 - 28 = 48

check sing eq(1):

7(48) = 12(28)

336 = 336

The two integers are 28 and 48.

Answer 2

Let x be the no. By the question, 7x+12x=76 19x=76 x=76/19 x=4 putting the value of x two integers are 7*4=28 and 12*4=48