integral of dx over x squared minus eight x plus 7

Question

help me. im stuck with this,,

integrate this using trigo sub.

Answer 1

Given ∫dx/(x^2 - 8x + 7)

∫dx/(x- 7)(x - 1)

By partializing....................... 

1/(x - 7)(x - 1)=1/6(x - 6) - 1/6(x - 1)

=1/6∫dx/(x - 7) - 1/6∫dx/(x - 1)

1/6ln (x - 7) - 1/6ln (x - 1) + c

= 1/6 ln {(x - 7)/(x - 1) + c