(x^3-9) / (x^2-1)

Question

How do you do this long division with missing powers

Answer 1

          x       

x²-1 ) x³  -9

          x³-x

              x-9

(x³-9)/(x²-1)=x+(x-9)/(x²-1) (quotient=x, remainder=x-9).

Another way of writing this: x³-9=x(x²-1)+x-9.