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1 Answer

sqrt(x) + sqrt(3x+4) = sqrt(6x+12)

a + b = c

(a + b)^2 = c^2

a^2 + 2ab + b^2 = c^2

x + 2 * sqrt(x) * sqrt(3x+4) + 3x + 4 = 6x + 12

2 * sqrt(x) * sqrt(3x+4) + 4x + 4 = 6x + 12

2 * sqrt(x) * sqrt(3x+4) = 2x + 8

a * b * c = d

a^2 * b^2 * c^2 = d^2

4 * x * (3x+4) = (2x+8)^2

12x^2 + 16x = (2x+8)^2

12x^2 + 16x = 4x^2 +32x + 64

8x^2 + 16x = 32x + 64

8x^2 - 16x = 64

8x^2 - 16x - 64 = 0

8 (x^2 - 2x - 8) = 0

8 (x-4) (x+2) = 0

x = -2, 4
by Level 13 User (103k points)

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