.001=100(.5)^(t/4.47)

regarding finding the age of a hypothetical meteorite
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1 Answer

0.001=100(.5)t/4.47,

0.00001=0.5t/4.47,

log(0.00001)=(t/4.47)log(0.5),

t=4.47log(0.00001)/log(0.5),

t=4.47×(-5)/log(0.5),

t=-22.35/log(0.5)=74.2451 approx.

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