solve the system using substitution {-5x+y=-4, 4x-4y=16}

You have to solve for Y for one which i don't know which one to do, then you have to plug it in for substitution but i dont really understand how to do that....anybody have any idea's?
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

{-5x+y=-4, 4x-4y=16}

y=5x-4

--> 4x-4(5x-4)=16

     4x-20x+16=16

     -16x+16=16

      -16x=0

        x=0

y=5(0)-4

y=0-4

y=-4

    

 

by Level 4 User (9.5k points)

Related questions

1 answer
Solve the linear system using substitution. y-5=x, 4x-y=9
asked Mar 18, 2013 in Algebra 1 Answers by anonymous | 679 views
2 answers
Solve, using the substitution method. 2x + 4y = 16 x – 7 = – 4y
asked Dec 17, 2013 in Algebra 1 Answers by Austinjb1998 Level 1 User (120 points) | 2.7k views
1 answer
solve using the substitution method 5x+8y=24, x=24-4y
asked Dec 17, 2013 in Other Math Topics by andijo Level 1 User (140 points) | 996 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!

Most popular questions within the last 3000 days

  1. 50+50-25X0+2+2= (19)
  2. it takes 10 road workers 5 days to complete a road repair when working 2 hours a day.Working at the same pace,how many days will it take 2 people working 5 hours a day to finish it? (3)
  3. Solve 15 -1(12÷4+1)? (4)
  4. 8:4(5+2) (3)
  5. How can i represent 1/3; 3/3; 7/3; 10/3 and 15/3 on a number line? (1)

Most popular tags

87,516 questions
100,279 answers
2,420 comments
732,207 users