solve the equation by factoring (3z-6)^-1/3 -5(3z-6)^-4/3=0
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Let y=(3z-6)-1/3,  y3=1/(3z-6), then y-5y4=0=y(1-5y3)=0 so y=0 or y3=⅕.

There is no solution for z if y=0, so y3=⅕=1/(3z-6), 3z-6=5, z=11/3.

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