For example, say I wanted to find a perfect square of the form
z^2 + 180z - 88

The solutions manual shows the answer is z = 22, but how do I figure out this kind of problem in general?

I am not looking for a zero of the quadratic. I'm looking for an integer generated by this quadratic form that is a perfect square.
Try completing the square?
pink chicken that wont help this person

assuming z^2+180-88=m^2

rewrite it in a form of z(z+180) = m^2 + 88

since LHS is a form of 2 factors z and z+180, the right handside must be also in such a form as a x b therefore m must have same factors as 88, you can start from there and try the factors of 88
answered Mar 7, 2011 by Level 3 User (2,140 points)

27+12+6=45   15+9+21=45                                                                   3+18+24=45

answered Jun 14, 2012 by anonymous
2,6,10,................................................................,142  is an AP

using this ap make magic square
answered Aug 14, 2012 by anonymous
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answered Sep 24, 2012 by anonymous
answered Feb 9, 2013 by (140 points)
answered Jun 4, 2013 by anonymous
49x^2+14x+1
answered Mar 17, 2014 by anonymous

wehh .!! bat ako tatanungin mo.

answered Jun 5, 2014 by yoyp
( e + 2a + q ) =
answered Jun 22, 2014 by anonymous
1. (a+b2) = (a+b) (a+b)
= a2+ab+ba+b2
= a2+2ab+b2

answered Jun 25, 2014 by Vanessa

Try working with the factors of 88.

z(z+180) = m^2 + 88

FACTORS OF 88:

The factors of 88