solve it please thanks
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2 Answers

y=(2/3)*x^-1

dy/dx=-1*(2/3)*x^-2

=-(2/3)x^-2
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What can you say about  the existence of a stationary point in the interval [-1,3] for the function ƒ(x) = x2-2x-3. Hint: Use Rolle’s Theorem.
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