Question

derivative of xlog3/x+tanx

Answer 1

Given (xlog3)/(x+tanx)
Using rule
[log(3)(tanx-x sec^2x)]/(x+tanx)^2

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Answer 2

f(x) = x * log (3/x) + tan(x)

log (3/x) = log(3) - log(x)

f(x) = x * log(3) - x * log(x) + tan(x)

f ' (x) = log(3) - log(x) - x * (1/x) + sec^2 (x)

f ' (x) = log(3) - log(x) - 1 + sec^2 (x)

f ' (x) = log(3/x) + sec^2 (x) - 1