Find L^(-1) [s/( s^2+16 )^2 ] using convolution

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ℒ-1{s/(s2+16)2} (inverse Laplace Transform).

ℒ{tsin(at)}=2as/(s2+a2)2, so if a=4, ℒ{tsin(4t)}=8s/(s2+16)2, therefore:

tsin(4t)=8ℒ-1{s/(s2+16)2} and ℒ-1{s/(s2+16)2}=⅛tsin(4t).

by Top Rated User (1.2m points)

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