This is a question from a calculus 1 class. I have no idea how to tackle this question.
asked Jan 30, 2013 in Trigonometry Answers by anonymous

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1 Answer

sin^2=1- cos^2, so using x as theta, 2-2cos^2x+cosx=2; 2cos^2x-cosx=0; cosx(2cosx-1)=0; cos x=0 or 0.5. x=(pi)/3 or 60°, (pi)/2 or 90°, 3(pi)/2 or 270°, 5(pi)/3 or 300°.

answered Mar 15, 2015 by Rod Top Rated User (493,620 points)
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