Sandwich Theorem Problem

Question

graph y=1-(x^2/6), y=(xsinx)/(2-2cosx), and y=1 together for -2 less than or equal to x less than or equal to 2. comment on the behavior of the graphs as x approaches 0

Answer 1

!!!!!! well..me ges yu spozed tu look at x tween -2 & +2

x^(2/60=x^(1/3)=kube root av x

as x gotu 0, kube root gotu 0

but for negativ x, kube root is negativ

1-kube root(x) gotu 1

##### as x gotu 0, xsine(x) gotu 0 twice

for small x, sine(x) approx=x, so top approx=x*x

kosine(x) gotu 1 so 2-2kosine(x) gotu 0

but yu hav x*sine(x)/[2*(1-kosine(x)]

=(x/2)*(sine(x)/[1-kosine(x)]

kosine(x) approx=1-x^2/2, so 1-kosine become +(1/2)x^2

but bottom hav 2* it, so bottom become x^2

& top become x^2

so this become 1