you need to estalished the identity so that what is the correct answer......

  1-cos2/1+sin=sin
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1 Answer

cos(2x)≡1-2sin2(x);

(1-cos(2x))/(1+sin(x))=sin(x),

2sin2(x)/(1+sin(x))=sin(x),

2sin2(x)=sin(x)+sin2(x),

sin2(x)-sin(x)=0,

sin(x)(sin(x)-1)=0, therefore sin(x)=0⇒x=nπ or sin(x)=1⇒x=π/2+2nπ=(4n+1)π/2, where n is an integer (including 0).

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