The 2 after 16t is actually a square root

Question

The function h is described by h(t)=-16t2+33.1t+124.26 gives the height of a ball thrown upward with a speed of 33.1 feet per second from a 124.26 ft high window t seconds after it is thrown until it hits the ground. What is the height of the ball 1.9 seconds after it is thrown?

Answer 1

RONG...NOT square root, tis square...accelerashun from gravity=-32.2 ft/sek^2

tu get hite (vertikal distans), gotta integerate speed

& speed=(start speed)-gt, weer g=accel from gravity

Teech's equashun...hite=-16t^2 +33.1t +124.26

evaluate at t=+1.9

t^2=3.61....-16*3.61=-57.76

33.1*t=33.1*1.9=+62.89

124.26 +62.89 -57.76=129.39