solve 20% alcohol solution with a 60% alcohol solution

Question

Juan needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 48% solution. How many millileters of each solution must Juan use?

A) Write an equation using the information as it is given above that can be used to solve this problem. Use as your variable to represent the quantity of 20% alcohol solution.

Answer 1

???????? yu meen yu kant just add water tu the 60% ????????

want 200 cc av 48%

hav 20% & 60%

0.2x +0.6y=200*48%=200*0.48=96

x+y=200, so y=200-x

0.2x +0.6*(200-x)=96

0.2x -0.6x +120=96

-0.4x=96-120=-24

x=+24/0.4

x=60

y=200-x=120