You need a 40% alcohol solution. On hand, you have a 600 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution?

A) Write an equation using the information as it is given above that can be used to solve this problem. Use x as your variable to represent the amount of pure water you need to use.

in Algebra 2 Answers by Level 1 User (740 points)

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1 Answer

????????? "tu obtaen the desired..." ????????? yu want sumthun ?????

600cc*85% x=0.85*600=510 cc av x

want this tu be 40% av y

510=0.4y, so y=510/0.4 =1,275 cc

gotta add=(1275 -600)

=675 cc yu gotta add
by

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