25=9 ln(1.8)(1.8^x)

Question

Starting Brief Calculus...and need a little help getting back in the swing of things after being out of math for a year...thank you.

Answer 1

25=9ln(1.8)(1.8^x)

(25/9)=ln(1.8^ x+1)

e^(25/9)=1.8^(x+1)

25/9=2.777777777...

e^2.7777777=16.0831155806775216863918087341 (approx)

take log(base100 av both sides

log[1.8^(x+1)]=(x+1)*log(1.8)=log(16.0831....)

so, x+1=log(16.0831)/log(1.8)....kan yuze NE base for the log

ln(16.083115580677216863918087341)=2.7777699999999

kall it 2.77777...kloes nuf

ln(1.8)=0.58778666490211897948228

so x+1=2.77777/0.5877866649...

x+1=4.7258132344029400...

x=3.72581323...