g(x)= (x)/(9-x) and h(x)= (x^3)-(6x^2)+3, calculate g(h(t))

g(x)= (x)/(9-x) and h(x)= (x^3)-(6x^2)+3, calculate g(h(t))
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1 Answer

g(x)= (x)/(9-x) and h(x)= (x^3)-(6x^2)+3, calculate g(h(t))

g(x) - (x) / (9 - x)

g(h) = (h) / (9 - h)

using h(t) = t^3 - 6t^2 + 3,

g(h(t)) = (t^3 - 6t^2 + 3) / (9 - t^3 + 6t^2 - 3)

g(h(t)) = (t^3 - 6t^2 + 3) / (6 - t^3 + 6t^2)

by Level 11 User (81.5k points)

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