sin^3xcos^2x=cos^2xsinx-cos^4xsinx

How would you prove the folowing:

sin^3xcos^2x=cos^2xsinx-cos^4xsinx
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1 Answer

sin³xcos²x=cos²xsinx-cos⁴xsinx.

Divide both sides by sinxcos²x:

sin²x=1-cos²x, which is true always.

by Top Rated User (1.2m points)

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