f'(x)=6x-8x^3, f(2)=3

It is asking to solve the differentail equation. PLEASE HELP!
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1 Answer

f'(x)=6x-8x3, so f(x)=3x2-2x4+c where c is a constant to be found.

f(2)=3=3(22)-2(24)+c=12-32+c=c-20,

c-20=3, c=23, f(x)=3x2-2x4+23.

by Top Rated User (1.2m points)

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