differentiate (3x^3)(sin x)

how to differentiate ? using product rule ?
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1 Answer

(3x^3)(sinx)

from the product rule

dy/dx = Vdu/dx + Udv/dx

U = 3x^3

du/dx = 9x^2

V = sinx

dv/dx = cosx

dy/dx = 9x^2sinx + 3x^3.cosx

(3x^3)(sinx)  =  9x^2sinx + 3x^3.cosx

by Level 3 User (4.0k points)

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