differentiate 1/(x^2+3x+5)^2 with respect to x

differentiate th function with respect to x
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1 Answer

Let u=x²+3x+5 and y=1/u².

du/dx=2x+3, dy/du=-2/u³.

dy/dx=(dy/du)(du/dx)=-2(2x+3)/u³=(-4x-6)/(x²+3x+5)³.

by Top Rated User (1.2m points)

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