Let the quadratic be q(x)=ax2+bx+c where a, b and c are constants.
q(-7)=-265=49a-7b+c,
q(0)=-6=c, so c=-6,
q(6)=-96=36a+6b+c.
Since we know c=-6 we have a pair of equations with two unknowns:
49a-7b-6=-265⇒49a-7b=-259⇒7a-b=-37 (1)
36a+6b-6=-96⇒36a+6b=-90⇒6a+b=-15 (2)
(1)+(2)=13a=-52, a=-4.
6a+b=-24+b=-15, b=9.
q(x)=-4x2+9x-6 is the quadratic.