Please help finding the distance
in Geometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Distance = Square root of (y2-y1)^2 + (x2-x1)^2

Subtract the y on the left from the y on the right like this

-9 - -17 = -9 + 17 = 8

square that

8^2 = 64

Thats the (x2-x1)^2 part

Subtract the x on the left from the x on the right like this

-4 - -19 = -4 + 19 = 15

square that

15^2 = 225

That's the (y2-y1)^2 part

Using the formula distance = square root of (y2-y1)^2 + (x2-x1)^2 we now have

Distance = Sqrt(64+225)

Distance = Sqrt(289)

Distance = 17

by Level 13 User (103k points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,533 users