2ln (x-3) = ln (x+5) + ln4

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2ln (x-3) = ln (x+5) + ln4
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1 Answer

2 ln(x-3) =ln(x+5) +ln(4)

ln[(x-3)^2] =ln[4*(x+5)]

(x-3)^2=4*(x+5)

x^2 -6x +9 -4x -20=0

x^2 -10x -11=0

(x+1)(x-11)=0
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