For a normal distribution that has a mean of 100 and a standard deviation of 8.  Determine the Z-score for each of the following X values:

       
       
       
       
       
       
       
X = 108 Z =    
       
X = 112 Z =    
       
X = 98 Z =    
       
X = 70 Z =    
       
X = 124 Z =    
       
       
Use the information in 1 A to determine the area or probability of the following:      
       
       
p(x > 108)      
       
p(x < 98)      
       
p(92 < x < 108)    
       
p(84 < x < 116)    
       
p(x < 84)      
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1 Answer

X Z=(X-100)/8 N(Z)
70 -3.75 1-0.9999=0.0001
84 -2 1-0.9772=0.0228
92 -1 1-0.8413=0.1587
98 -0.25 1-0.5987=0.4013
108 1 0.8413
112 1.5 0.9332
116 2 0.9772
124 3 0.9987

The diagrams (not to scale) below symbolically explain the arithmetic.

P(X>108)=1-0.8413=0.1587

P(X<98)=0.4013

P(92<X<108)=0.8413-0.1587=0.6826

P(84<X<116)=0.9772-0.0228=0.9544

P(X<84)=0.0228

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