the square root of 3n +6 set equal to 4-n

i need to know how to solve this equation
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1 Answer

root(3n+6) =(4-n)

3n+6=n^2-8n+16

n^2 -8n -3n+16-6=0

n^2 -11n +10=0

(n-1)(n-10)=0
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