how do you factor: 4x^3y-7ab^3

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1 Answer

p3-q3=(p-q)(p2+pq+q2) so if p3=4x3y, then p=x∛(4y) and, if q3=7ab3, then q=b∛(7a).

4x3y-7ab3=(x∛(4y)-b∛(7a))(x2∛(16y2)+bx∛(28ay)+b2∛(49a2)).

by Top Rated User (1.2m points)

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