If the coefficient of static friction is 0.380, what is the normal force acting on the box?

A force of 16.0 newtons is sufficient to set a box that is at rest into motion. If the coefficient of static friction is 0.380, what is the normal force acting on the box?
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2 Answers

foers=16/0.38=42.1052...

yu shuer the foers is "normal"

maebee its straenj
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16.0/.380= 42.1 N= Normal Force
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