A 60 kg person on skis is going down a hill sloped at 37 degrees the coefficient of kinetic friction between the skis and the snow is 0.15 what is the skier’s acceleration down the slope?

Question

Give the answer in meters per second. It is a physics problem.

Answer 1

The normal force on the slope is 60gcos37 Newtons and the frictional force resulting from this is 0.15×60gcos37 Newtons. The force down the slope in the absence of friction is 60gsin37 (g=acceleration of gravity=9.81m/s²). The frictional force counteracts the gravitational force so the net force is 60gsin37-0.15×60gcos37 N. F=ma where m=mass and a=acceleration, so 60a=60gsin37-0.15×60gcos37.

We can divide through by 60: a=g(sin37-0.15cos37)=9.81(0.4820)=4.73m/s² approx.