Find the Standard Form of the equation of the Line w/ slope -3 passing through the point (6, -5)

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1 Answer

me assume yu meen slope=-3 & point=(6,-5)

y=slope*x+konst

y=-3x+konst

translate x from 6 bak tu y-axis...deltax=-6

deltay=slope*deltax=(-3)*(-6)=+18

y-intersept=-5+18=13

y=-3x+13
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