Find N when t=6

Question

bacterial growth rate is found to satisfy the following equation dN/dt=0.5N where N is number of bacteria and t is time in day.Find N when t=6, given initial number of bacteria is 200.

Answer 1

integrate 0.5n, me get N=n start(1/4)t^2

???? start kount=200 at time=1 ???

if so, Nstart=200=konst*t^2

konst=200

t=6...6^2=36

kount=200*36=7200

Answer 2

Theez problems oft R based on the dubel time=delta time for the

germ kount tu dubel

Then yu kount the number av such time steps

& germ kount/start germ kount=2^number time steps

alternut wae is assume exponential

raesheo=(kount at time 0)/(kount at  late time)=konst*e^ fakter*(delta time)