find and equation of a line that satisfies the given condition.

the line passign through (-5,-4) and parallel to the line passing through (-3,2) and (6,8)
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1 Answer

Slope of the given line: (8-2)/(6-(-3))=6/9=⅔.

The equation of the parallel line (same slope):

y+4=⅔(x+5), 3y+12=2x+10, 3y=2x-2, y=(4/3)(x-1).

This can also be written 2x-3y=2.
by Top Rated User (1.2m points)

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