Help me. This is for my HW.
in Trigonometry Answers by Level 1 User (140 points)

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2 Answers

sinA+sinB=2sin((A+B)/2)cos((A-B)/2), so sin((A+B)/2)cos((A-B)/2)=1/2(sinA+sinB).

(1/2)(A+B)=5x and (1/2)(A-B)=3x, therefore, adding these two equations: A=8x and subtracting them: B=2x.

Therefore, (1/2)(sin8x+sin2x)=sin5xcos3x.

by Top Rated User (839k points)

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