Finding the slope of tangent line at given point?

I need to find the the slope of the line tangent to 3x^2+xy-4y^3=108 which also passes through point (6,0).
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2 Answers

6x+y + xy ' - 12y^2 y'=0
substitute (6,0) ---> y ' = -6
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find the slope and equation of tangent line at the given point. f(x)= x2 + 11x - 15 ; x = 1
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