2sin(7x-3pi/8)-root3=0

need to know how i would go about solving this problem, i know theres 4 answers and i know what they are but i dont know how to get them, thank you
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1 Answer

2sin(7x-⅜π)=√3,

sin(7x-⅜π)=√3/2,

7x-⅜π=⅓π because sin(⅓π)=√3/2.

7x=π(⅓+⅜)=17π/24,

x=17π/168 (about 18.21°).
by Top Rated User (1.2m points)

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