I guess you mean the factors.
1240020=22×32×5×832.
From this breakdown, the prime factors are 2, 3, 5, 83. We also have 1 and 1240020, of course.
So the factors (of which there are many) are any product of the numbers:
2, 2, 3, 3, 5, 83, 83. There are 7 numbers here. In addition to the prime factors, we can take pairs of numbers, for example, to find 9 more factors:
2×2=4, 2×3=6, 2×5=10, 2×83=166, 3×3=9, 3×5=15, 3×83=249, 5×83=415, 83×83=6889.
Then we can take the product of a set of three of these 7 numbers:
2×2×3=12, 2×2×5=20, 2×2×83=332, 2×3×3=18, 2×3×5=30, 2×3×83=498, 2×5×83=830, 2×83×83=13778, 3×3×5=45, 3×3×83=747, 3×5×83=1245, 3×83×83=20667, 5×83×83=34445. Etc.
If we divide 1240020 by each of the factors already identified we get the remaining factors. When we divide by the 4 prime factors we get 4 more factors which are each products of the remaining 6 numbers. When we divide 1240020 by each of the pair products we get another 9 factors (5-number products), and when we divide by 3-number products we get another 13 factors (4-number products).
Here, in order, are all 52 factors:
1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45,
60, 83, 90, 166, 180, 249, 332, 415, 498, 747,
830, 996, 1245, 1494, 1660, 2490, 2988, 3735,
4980, 6889, 7470, 13778, 14940, 20667, 27556,
34445, 41334, 62001, 68890, 82668, 103335,
124002, 137780, 206670, 248004, 310005,
413340, 620010, 1240020.
You may want to discard 1 and 1240020 as trivial factors.