ʃ{(x4 +1)/x2}dx
asked Aug 13, 2012 in Calculus Answers by anonymous

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1 Answer

qn:(x^4 + 1).x^2 

∫(x^2 + x^-2) dx

=1/3.x^(3) - 1/x + c

∫(x^4 + 1).x^2 = (x^4 - 3)/3x + c

answered May 23, 2014 by stanny rusota Level 3 User (4,020 points)
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