(xy^2 +x)dx + (yx^2 +y)dy = 0
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1 Answer

(xy^2 +x)dx + (yx^2 +y)dy = 0

You can spot this one by inspection. Start by multiplying all terms by 2.

2(xy^2 +x)dx + 2(yx^2 +y)dy = 0

(2xy^2dx + 2x^2ydy) + 2xdx + 2ydy = 0

d(x^2y^2) + d(x^2) + d(y)2) = 0

Integrating,

x^2y^2 + x^2 + y^2 = const

by Level 11 User (81.5k points)

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