where defined x^2-9/x+2/x-3/x-2

So confused!!
in Algebra 1 Answers by Level 1 User (200 points)

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1 Answer

Multiply the first fraction by the  reciprocal of the second fraction.

(x^2-9/x+2)(x-2/x-3)

={(x^2-9)(x-2)}/{(x+2)(x-3)}

={(x+3)(x-3)(x-2)}/{(x+2)(x-3)}

={(x+3)(x-2)}/(x+2)

 

 

by Level 8 User (32.3k points)

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