limit of (6x-2sin(3x))/5x^3 as x approaches 0
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

sin(3x)=3x-27x^3/6 approx when x is small, so the expression becomes 6x-6x+9x^3/5x^3=9/5=1.8 as x approaches 0.

by Top Rated User (1.2m points)

Related questions

2 answers
asked Mar 16, 2013 in Calculus Answers by anivish Level 1 User (120 points) | 5.0k views
1 answer
1 answer
asked Sep 29, 2021 in Calculus Answers by anonymous | 947 views
1 answer
0 answers
asked Oct 31, 2018 in Calculus Answers by Bibin | 554 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,308 answers
2,420 comments
750,649 users