Differentiate of e^2x.tan(x/3)
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Let u=e2x and v=tan(x/3). du/dx=2e2x and dv/dx=⅓sec2(x/3).

d(uv)/dx=vdu/dx+udv/dx=2e2xtan(x/3)+⅓e2xsec2(x/3).

This solution can be expressed in different ways: factoring out e2x and/or using the identity sec2(x/3)=1+tan2(x/3).

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