If 4cot^45°-sec^60°+sin^60°+p=3/4 then find the value of p

Question

Trigonometry evaluation for which we have to find the value of p by evaluating this trigonometric identities.

Answer 1

cot(45°)=tan(45°)=1, cot²(45°)=1; sec(60°)=1/cos(60°)=1/½=2, sec²(60°)=4;

4cot²(45°)-sec²(60°)=4-4=0.

sin²(60°)=1-cos²(60°)=1-¼=¾;

¾+p=¾, so p=0.

Answer 2

4Cot²45°-Sec²60°+sin²60°+p=3/4 Solution - 4(1)² -(2)²+(√3/2)²+p=3/4 =4 - 4 +3/4 + p =3/4 = 0 + 3/4 +p = 3/4 = P = 3/4 - 3/4 p = 0 Answer

Answer 3

4cot²45-sec²60+sin²60+p=3/4. 4(1)²- 2²+(^3/2)²+p=3/4 4-4+3/4+p=3/4 0+3/4+p=3/4 P=3/4-3/4 P=3-3/4 P=0/4 P=0